7/(y^2+y)＋3/(y^2-y)=6/(y^2-1)

7/(y^2+y)＋3/(y^2-y)=6/(y^2-1)
=>
7/y(y+1)+3/y(y-1)=6/(y+1)(y-1)

通分
=>
7(y-1)/y(y+1)(y-1) +3(y+1)/y(y+1)(y-1)-6y/y(y+1)(y-1)=
(7y-7+3y+3-6y)/y(y+1)(y-1) =0
(4y-4)/y(y+1)(y-1)=0
y-1=0
y=1
这样分母为0
所以无解
要么就是题目抄错了